Svelte 使用编译器来构建代码,从而优化渲染。默认情况下,组件只运行一次,除非它们在标记中被引用。要能够响应选项的变化,您需要使用 stores。
在下面的示例中,refetchInterval 选项是从变量 intervalMs 设置的,该变量已绑定到输入字段。但是,由于查询无法响应 intervalMs 的变化,因此当输入值更改时,refetchInterval 不会改变。
<script lang="ts">
import { createQuery } from '@tanstack/svelte-query'
const endpoint = 'https://:5173/api/data'
let intervalMs = 1000
const query = createQuery({
queryKey: ['refetch'],
queryFn: async () => await fetch(endpoint).then((r) => r.json()),
refetchInterval: intervalMs,
})
</script>
<input type="number" bind:value={intervalMs} />
<script lang="ts">
import { createQuery } from '@tanstack/svelte-query'
const endpoint = 'https://:5173/api/data'
let intervalMs = 1000
const query = createQuery({
queryKey: ['refetch'],
queryFn: async () => await fetch(endpoint).then((r) => r.json()),
refetchInterval: intervalMs,
})
</script>
<input type="number" bind:value={intervalMs} />
为了解决这个问题,我们可以将 intervalMs 转换为一个可写 store。然后可以将查询选项转换为一个派生 store,该 store 将被传递给具有真正响应性的函数。
<script lang="ts">
import { derived, writable } from 'svelte/store'
import { createQuery } from '@tanstack/svelte-query'
const endpoint = 'https://:5173/api/data'
const intervalMs = writable(1000)
const query = createQuery(
derived(intervalMs, ($intervalMs) => ({
queryKey: ['refetch'],
queryFn: async () => await fetch(endpoint).then((r) => r.json()),
refetchInterval: $intervalMs,
})),
)
</script>
<input type="number" bind:value={$intervalMs} />
<script lang="ts">
import { derived, writable } from 'svelte/store'
import { createQuery } from '@tanstack/svelte-query'
const endpoint = 'https://:5173/api/data'
const intervalMs = writable(1000)
const query = createQuery(
derived(intervalMs, ($intervalMs) => ({
queryKey: ['refetch'],
queryFn: async () => await fetch(endpoint).then((r) => r.json()),
refetchInterval: $intervalMs,
})),
)
</script>
<input type="number" bind:value={$intervalMs} />